Codeforces Round #248 (Div. 2) B - Kuriyama Mirai's Stones Solution
Solution in C++:
///La ilaha illellahu muhammadur rasulullah
///******Bismillahir-Rahmanir-Rahim******///
///Abul Hasnat Tonmoy
///Department of CSE,23rd batch
///Islamic University,Bangladesh
#include <bits/stdc++.h>
using namespace std;
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
int n,i,m,t,l,r;
cin>>n;
long long int a[n+1],b[n+1],sum1[n+1],sum2[n+2];
for(i=1; i<=n; i++)
{
cin>>a[i];
b[i]=a[i];
}
sum1[0]=0,sum2[0]=0;
for(i=1; i<=n; i++)
sum1[i]=sum1[i-1]+a[i];
sort(b+1,b+n+1);
for(i=1; i<=n; i++)
sum2[i]=sum2[i-1]+b[i];
cin>>m;
for(i=0; i<m; i++)
{
cin>>t>>l>>r;
if(t==1)
cout<<sum1[r]-sum1[l-1]<<endl;
else
cout<<sum2[r]-sum2[l-1]<<endl;
}
return 0;
}
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